If a larger value of resistance were used with the same value of capacitance in the above circuit, then a smaller current would flow, therefore it would take longer for the capacitor to charge up and ...
The gradient of this graph is equal to the capacitance of the capacitor. \(C= \frac{Q}{V}\) And the area under the graph is the energy stored by the capacitor.
Some results have been hidden because they may be inaccessible to you
Show inaccessible results
Feedback